435

$\left(x-1\right)\left(x+1\right)\left(2x-3\right)=\left(x^2+1\right)\left(2x-3\right)=2x^2-3x^2+2x-3=-x^2+2x-3$

$\left(2x+1\right)\left(3x-1\right)\left(x+2\right)=\left(6x^2-x-1\right)\left(x+2\right)=6x^3-x^2-x+12x^2-2x-2=6x^3+11x^2-3x-2$