372

a)
6x^2-x-2
x=\frac{1\pm7}{12}=\frac{2}{3}\ tai\ -\frac{1}{2}
6\left(x-\frac{2}{3}\right)\left(x+\frac{1}{2}\right)
b)
10x^2+x-3
x=\frac{-1\pm11}{20}=\frac{1}{2\ }\ tai\ -\frac{3}{5}
10\left(x-\frac{1}{2}\right)\left(x+\frac{3}{5}\right)