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a)
x^2-6x+9=100
\left(x-3\right)^2=100
\sqrt{\left(x-3\right)^2}=\sqrt{100}
x-3=10
x=13
b)
x^2-6x+5=0
x^2-6x=-5
x^2-2x\cdot3+3^2=-5+3^2
\left(x-3\right)^2=4
\sqrt{\left(x-3\right)^2}=\sqrt{4}
x-3=2
x=5
c)
2x^2+12x+8=0
2x^2+2\cdot2x\cdot3+8+1=1
\left(2x+3\right)^2=1
\sqrt{\left(2x+3\right)^2}=\sqrt{1}
2x+3=1
2x=-2
x=-1