141

$\left|x+1\right|<\left|x-2\right|\ \ \ \mid^2$
$\left(\right|x+1\left|\right)^2-\left(\right|x-2\left|\right)^2<0$
$x^2+2x+1<x^2-4x+4$
$6x<3$
$x<\frac{1}{2}$

$\left|2-2x\right|\ge\left|5+2x\right|\ \ \ \mid^2$
$4x^2-8x+4\ge4x^2+20x+25$
$-28x-21\ge0$
$-28x\ge21$
$x\le-\frac{3}{4}$