109

$3^1+3^0+3^{-1}=3+1+\frac{1}{3}=4\ \frac{1}{3}$

$4^{-2}+2^{-1}-2^1=\frac{1}{16}+\frac{1}{2}-2=\frac{9}{16}-2=-\frac{23}{16}$

$\frac{1}{10}-10^{-2}+0{,}02=0{,}1-\frac{1}{100}+0{,}02=0{,}11$

$-3^{-2}+\left(-6\right)^{-2}=-\frac{1}{9}+\frac{1}{36}=-\frac{4}{36}+\frac{1}{36}=-\frac{3}{36}=-\frac{1}{12}$