Kertaus3

$\lim_{x\rightarrow3}\frac{2x+3}{x-1}=\frac{2\cdot3+3}{3-1}=\frac{9}{2}$

$\lim_{x\rightarrow0}\frac{2x^2-4\ x}{2x}=\lim_{x\rightarrow0}\frac{2x\left(x-2\right)}{2x}$

$=\lim_{x\rightarrow0}\left(x-2\right)=0-2=-2$

c)

$\lim_{x\rightarrow3}\frac{x^2-3\ x}{x-3}=\lim_{x\rightarrow3}\frac{x\left(x-3\right)}{x-3}$

$=\lim_{x\rightarrow3}\ x=3$

$\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}=\lim_{x\rightarrow2}\ \frac{\left(x-2\right)\left(x+2\right)}{x-2}$

$=\lim_{x\rightarrow2}\ \left(x+2\right)\ =2+2=4$

$\lim_{x\rightarrow2}\ \frac{x^2-4}{4-x^2}=\lim_{x\rightarrow2}\ \frac{x^2-4}{-\left(-4+x^2\right)}$

$=\lim_{x\rightarrow2}\ \frac{x^2-4}{-\left(x^2-4\right)}=\lim_{x\rightarrow2}\ \frac{1}{-1}=-1$