Teksti

439

$28$

$h=\frac{4-\left(-2\right)}{3}=2$

$\int_{-2}^4\left(x^2-3x+3\right)dx=2\left(\frac{1}{2}f\left(-2\right)+f\left(0\right)+f\left(2\right)+\frac{1}{2}f\left(4\right)\right)=2\left(6{,}5+3+1+3{,}5\right)=28$

442

$\int_0^2f\left(x\right)dx=0{,}5\left(\frac{1}{2}f\left(0\right)+f\left(0{,}5\right)+f\left(1\right)+f\left(1{,}5\right)+\frac{1}{2}f\left(2\right)\right)=\frac{\left(1+1-3-5-3\right)}{2}=-4{,}5$

$\int_0^2f\left(x\right)dx=\frac{0{,}5}{3}\left(f\left(0\right)+4f\left(0{,}5\right)+2f\left(1\right)+4f\left(1{,}5\right)+f\left(2\right)\right)=\frac{0{,}5}{3}\left(2+4-6-20-6\right)=-4{,}33333...\approx-4{,}3$