Experiment

Based on the formula standard gravity, the value of [[$ g $]]​ can be calculated using the distance of the fall [[$ s $]]​ and the squre of the period of time of the fall [[$ t^2 $]]​. This means that in subsequent experiment, it is important to measure the period of time accurately and precisely, as its exponent in the formula emphasizes the error two-fold. On the other hand, all errors are balanced by repeating the experiment several times under the same conditions.

Before the actual experiment, state your name.


Now you are free to go!
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]

As an average, [[$ \bar{g} = \frac{\sum g}{10} = $]] [[$\frac{\text{m}}{\text{ s}^2}$]].
Roskapostituksen esto
Valitse mikä tahansa numero, joka on suurempi kuin 2.

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