Determining standard gravity g

Theory

Let us assume there is an object in free fall. To make the mathematics easier to cope with, we may also assume that air resistance does not affect the fall of our object.

The fall of the object is determined by the standard gravity [[$ g $]]​ of Earth.  It can be deduced that after falling for a period of time [[$ t $]]​, the height of the fall [[$ s $]]​ is given by the formula:
​[[$$ s = \frac{1}{2}gt^2 \quad $$]]​
Let us solve this for standard gravity [[$ g $]]​. Using algebra, or equation-solving, we get
[[$$ s = \frac{1}{2}gt^2 \quad ||\cdot 2 $$]]​​
​[[$$ 2s = gt^2 \quad ||:t^2 $$]]​
​[[$$ \frac{2s}{t^2} = g \quad$$]]​
[[$$ g = \frac{2s}{t^2} \quad$$]]​

Experiment

Based on the formula standard gravity, the value of [[$ g $]]​ can be calculated using the distance of the fall [[$ s $]]​ and the squre of the period of time of the fall [[$ t^2 $]]​. This means that in subsequent experiment, it is important to measure the period of time accurately and precisely, as its exponent in the formula emphasizes the error two-fold. On the other hand, all errors are balanced by repeating the experiment several times under the same conditions.

Before the actual experiment, state your name.


Now you are free to go!
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]
[[$ s = $]] m, [[$ t = $]] s [[$\Rightarrow$]] [[$ g = \frac{2s}{t^2} = $]] [[$\frac{\text{m}}{\text{s}^2}$]]

As an average, [[$ \bar{g} = \frac{\sum g}{10} = $]] [[$\frac{\text{m}}{\text{ s}^2}$]].
Roskapostituksen esto
Valitse mikä tahansa numero, joka on suurempi kuin 2.