S.100 3-4


1C=1CO_2
2H=1H_2O
n\left(C\right)=n\left(CO_2\right)=\frac{0{,}228g}{\left(12{,}01+2\cdot16{,}00\right)\frac{g}{mol}}=0{,}0051806...mol
n\left(H\right)=2\cdot n\left(H_2O\right)=2\cdot\frac{0{,}0931g}{\left(2\cdot1{,}008+16{,}00\right)\frac{g}{mol}}=0{,}010335...mol
Lasketaan palaneessa yhdisteessä ollen hiilen ja vedyn massat
 
m\left(C\right)=0{,}005180...mol\cdot12{,}01\frac{g}{mol}\approx0{,}0622195g
m\left(H\right)=0{,}010335...mol\cdot1{,}008\frac{g}{mol}\approx0{,}0104179g
Hapen massa
m\left(O\right)=0{,}100g-0{,}0622195g-0{,}0104179g=0{,}0273626g
Hapen ainemäärä
n\left(O\right)=\frac{0{,}0273626g}{16{,}00\frac{g}{mol}}=0{,}00171016...mol
Lasketaan hiilen, vedyn sekä hapen ainemäärien suhde
\frac{n\left(C\right)}{n\left(O\right)}\approx3
\frac{n\left(H\right)}{n\left(O\right)}\approx6
\frac{n\left(O\right)}{n\left(O\right)}=1
C:H:O\approx3:6:1=\left(C_3H_6O\right)_x