S.93 10-6

$V_1=75cm^3=75\cdot10^{-6}m^3$
$V_2=33cm^3=33\cdot10^{-6}m^3$
$p_1=101{,}3kPa$
$p_2=x$
$t_1=18°C=18°C\ +273{,}15=291{,}15K$
$t_2=37°C=37°C+273{,}15=310{,}15K$
$\frac{p_1V_1}{T_1}=\frac{p_2V_2}{T_2}$ , jolloin $p_1V_1T_2=p_2V_2T_1$

Jolloin

$p_2=\frac{p_1V_1T_2}{V_2T_1}=\frac{101{,}3kpa\cdot75\cdot10^{-6}m^3\cdot310{,}15K}{33\cdot10^{-6}m^3\cdot291{,}15K}=245{,}2515...\approx245{,}3kPa=0{,}25mPa$