\sin^2x-\cos^2x=\frac{1}{2} \
\sin^2x-\left(1-\sin^2x\right)=\frac{1}{2} \
\Rightarrow 2\sin^2x=\frac{3}{2} \
\sin^2x=\frac{3}{4} \text{ siis } \sin x=\pm \frac{\sqrt{3}}{2}

A = Intersect(xAxis, yAxis)
c = Circle(A, 1)
B = Intersect(c, yAxis, 1)
C = Intersect(c, xAxis, 2)
d = CircleArc(A, B, C)
f: y = sqrt(3) / 2
g: y = ((-sqrt(3))) / 2
D = Intersect(d, g)