α

α=16°/2=8°

r

r

150m

221.

Ratkaistaan r suorakulmaisesta kolmiosta (1).
Halkaisija säteen avulla(2).

V: Halkaisija on 49m.

223.

r=6370km

(6370+3.718)km

Teide

Afrikka

b=?

β

3718m=3.718km
Ratkaistaan keskuskulma β
suorakulmaisesta kolmiosta (4). 

Sitten kysytty kaaren pituus kaavalla(7).

V: Etäisyys on 218km

cos(β)=\frac{6370}{6370+3.718}

A = (-1.54, 2.6)
B = (-1.08, 4)
c = Circle(A, B)
C = (5.08, 2.38)
f, g = Tangent(C, c)
D = Intersect(c, f, 1)
kuvio1, c_1, a, d = Polygon(A, D, C)
vahvuus1 = PolyLine((3.14, 2.4400000000000004), (NaN, NaN), (3.14, 2.4400000000000004), (3.1, 2.5000000000000004), (3.08, 2.5600000000000005), (3.08, 2.64), (3.08, 2.72), (3.08, 2.8000000000000003), (3.08, 2.8800000000000003), (3.14, 2.9200000000000004), true)
lista1: {}
E = (-0.8, -5.06)
F = (1.06, -3.94)
e = Circle(E, F)
h = Segment(E, F)
G = (1.78, -3.46)
i = Segment(F, G)
j, k = Tangent(G, e)
H = Intersect(e, j, 1)
l = Segment(E, H)
α = Angle(E, H, G)
vahvuus2 = PolyLine((-0.42, -4.819999999999997), (NaN, NaN), (-0.42, -4.819999999999997), (-0.48, -4.779999999999997), (-0.54, -4.719999999999996), (-0.62, -4.699999999999997), (-0.68, -4.639999999999996), (-0.78, -4.639999999999996), true)
kuvio2, g_1, e_1, h_1 = Polygon(E, H, G)
lista2: {}
γ = Angle(A, D, C)