https://peda.net/id/f962e87814f 2020-10-23T08:31:17+03:00 https://peda.net/:static/535/peda.net.logo.bg.svg <div class="license">Tämän sivun lisenssi <a rel="license" href="https://peda.net/info">Peda.net-yleislisenssi</a></div> https://peda.net/id/8f2334e614f 2020-10-23T09:32:44+03:00 <div>a)</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BOH%5E-%5Cright%5D%3D%5Cfrac%7BK_w%7D%7B%5Cleft%5BH_3O%5E%2B%5Cright%5D%7D%3D%5Cfrac%7B1%7B%2C%7D008%5Ccdot10%5E%7B-14%7D%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%7B1%7B%2C%7D0%5Ccdot10%5E%7B-7%7D%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%3D1%7B%2C%7D008%5Ccdot10%5E%7B-7%7D" alt="\left[OH^-\right]=\frac{K_w}{\left[H_3O^+\right]}=\frac{1{,}008\cdot10^{-14}\frac{mol}{dm^3}}{1{,}0\cdot10^{-7}\ \frac{mol}{dm^3}}=1{,}008\cdot10^{-7}"/> pH=7, neutraali</div> <div>b)</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BOH%5E-%5Cright%5D%3D%5Cfrac%7BK_w%7D%7B%5Cleft%5BH_3O%5E%2B%5Cright%5D%7D%3D%5Cfrac%7B1%7B%2C%7D008%5Ccdot10%5E%7B-14%7D%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%7B1%7B%2C%7D9%5Ccdot10%5E%7B-11%7D%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%3D5%7B%2C%7D305%5Ccdot10%5E%7B-4%7D" alt="\left[OH^-\right]=\frac{K_w}{\left[H_3O^+\right]}=\frac{1{,}008\cdot10^{-14}\frac{mol}{dm^3}}{1{,}9\cdot10^{-11}\ \frac{mol}{dm^3}}=5{,}305\cdot10^{-4}"/>pH=10,72, emäksinen</div> <div>c)</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BOH%5E-%5Cright%5D%3D%5Cfrac%7BK_w%7D%7B%5Cleft%5BH_3O%5E%2B%5Cright%5D%7D%3D%5Cfrac%7B1%7B%2C%7D008%5Ccdot10%5E%7B-14%7D%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%7B6%7B%2C%7D7%5Ccdot10%5E%7B-4%7D%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%3D1%7B%2C%7D504%5Ccdot10%5E%7B-11%7D" alt="\left[OH^-\right]=\frac{K_w}{\left[H_3O^+\right]}=\frac{1{,}008\cdot10^{-14}\frac{mol}{dm^3}}{6{,}7\cdot10^{-4}\ \frac{mol}{dm^3}}=1{,}504\cdot10^{-11}"/>pH=3,173, hapan</div> <div>d)</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BOH%5E-%5Cright%5D%3D%5Cfrac%7BK_w%7D%7B%5Cleft%5BH_3O%5E%2B%5Cright%5D%7D%3D%5Cfrac%7B1%7B%2C%7D008%5Ccdot10%5E%7B-14%7D%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%7B2%7B%2C%7D3%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%3D4%7B%2C%7D382%5Ccdot10%5E%7B-15%7D" alt="\left[OH^-\right]=\frac{K_w}{\left[H_3O^+\right]}=\frac{1{,}008\cdot10^{-14}\frac{mol}{dm^3}}{2{,}3\ \frac{mol}{dm^3}}=4{,}382\cdot10^{-15}"/>pH=-0,36, hapan</div> <div> </div> <div> </div> 2020-10-23T09:32:44+03:00 https://peda.net/id/108b78d414f 2020-10-23T09:14:53+03:00 a)<br/> <img src="https://i.imgur.com/ydc7Vyt.png"/><br/> b)<br/> reaktio on endoterminen, sillä lämpötilan kasvaessa tasapainovakio kasvaa eli tasapaino siirtyy reaktiotuotteiden suuntaan<br/> c)<br/> <img src="https://math-demo.abitti.fi/math.svg?latex=K_w%5C%20%5Cleft(%2B30%C2%B0C%5Cright)%3D1%7B%2C%7D33%5Ccdot10%5E%7B-14%7D" alt="K_w\ \left(+30°C\right)=1{,}33\cdot10^{-14}"/><br/> d)<br/> <div><img src="https://math-demo.abitti.fi/math.svg?latex=K_w%3D5%7B%2C%7D476%5Ccdot10%5E%7B-14%7D%5Cleft(mol%5Ctext%7B%2F%7Ddm%5E3%5Cright)%5E2%3D%5Cleft(2%7B%2C%7D341%5Ccdot10%5E%7B-7%7D%5C%20mol%5Ctext%7B%2F%7Ddm%5E3%5Cright)%5E2" alt="K_w=5{,}476\cdot10^{-14}\left(mol\text{/}dm^3\right)^2=\left(2{,}341\cdot10^{-7}\ mol\text{/}dm^3\right)^2"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BH_3O%5E%2B%5Cright%5D%3D%5Cleft%5BOH%5E-%5Cright%5D%3D2%7B%2C%7D341%5Ccdot10%5E%7B-7%7D%5Cfrac%7Bmol%7D%7Bdm%5E3%7D" alt="\left[H_3O^+\right]=\left[OH^-\right]=2{,}341\cdot10^{-7}\frac{mol}{dm^3}"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=pH%3D-%5Clg%5Cleft%5BH_3O%5E%2B%5Cright%5D%3D6%7B%2C%7D6306...%5Capprox6%7B%2C%7D6" alt="pH=-\lg\left[H_3O^+\right]=6{,}6306...\approx6{,}6"/></div> e)<br/> koska puhtaassa vedessä oksonium- ja hydroksidi-ionikonsentraatio ovat samat 2020-10-23T09:14:53+03:00