Työ 13
https://peda.net/id/f3f0d6fc1d0
2020-11-02T14:28:46+02:00
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Työ 13
https://peda.net/id/0f7364c01d1
2020-11-02T15:48:17+02:00
1.<br/>
<img src="https://i.imgur.com/ZwPryp9.png"/><br/>
2.<br/>
<img src="https://i.imgur.com/stNB1bI.png"/><br/>
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<div>0,10 mol/l NaOHia tarvittiin 22,59ml neutraloimaan 20ml happoa </div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=c%3D%5Cfrac%7Bn%7D%7BV%7D" alt="c=\frac{n}{V}"/><br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=n%3DcV" alt="n=cV"/><br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=n%3D0%7B%2C%7D10%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%5Ccdot0%7B%2C%7D02259l%3D0%7B%2C%7D002259mol" alt="n=0{,}10\ \frac{mol}{l}\cdot0{,}02259l=0{,}002259mol"/></div>
<div>hapon konsentraatio</div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=c%3D%5Cfrac%7Bn%7D%7BV%7D%3D%5Cfrac%7B0%7B%2C%7D002259mol%7D%7B0%7B%2C%7D020l%7D%3D0%7B%2C%7D11295%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="c=\frac{n}{V}=\frac{0{,}002259mol}{0{,}020l}=0{,}11295\ \frac{mol}{l}"/><br/>
3.<br/>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cbegin%7Barray%7D%7Bl%7Cl%7D%0A%26HA%5Cleft(aq%5Cright)%26H_2O%5Cleft(l%5Cright)%26A%5E-%5Cleft(aq%5Cright)%26H_3O%5E%2B%5Cleft(aq%5Cright)%5C%5C%0A%5Chline%0Ac_%7Balku%7D%260%7B%2C%7D11295%26-%260%260%7B%2C%7D00301995...%5C%5C%0Amuutos%26%26-%26%26%5C%5C%0Ac_%7Btasap%7D%26%26-%26%26%0A%5Cend%7Barray%7D" alt="\begin{array}{l|l} &HA\left(aq\right)&H_2O\left(l\right)&A^-\left(aq\right)&H_3O^+\left(aq\right)\\ \hline c_{alku}&0{,}11295&-&0&0{,}00301995...\\ muutos&&-&&\\ c_{tasap}&&-&& \end{array}"/></div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=pH%3D2%7B%2C%7D52" alt="pH=2{,}52"/><br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=10%5E%7B-2%7B%2C%7D52%7D%3D0%7B%2C%7D00301995...%3D%5Cleft%5BH_3O%5E%2B%5Cright%5D" alt="10^{-2{,}52}=0{,}00301995...=\left[H_3O^+\right]"/><br/>
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<img src="https://math-demo.abitti.fi/math.svg?latex=%5Cbegin%7Barray%7D%7Bl%7Cl%7D%0A%26HA%5Cleft(aq%5Cright)%26H_2O%5Cleft(l%5Cright)%26A%5E-%5Cleft(aq%5Cright)%26H_3O%5E%2B%5Cleft(aq%5Cright)%5C%5C%0A%5Chline%0Ac_%7Balku%7D%260%7B%2C%7D11295%26-%260%260%5C%5C%0Amuutos%26-0%7B%2C%7D00301995...%26-%26%2B0%7B%2C%7D00301995...%26%2B0%7B%2C%7D00301995...%5C%5C%0Ac_%7Btasap%7D%260%7B%2C%7D10993%26-%260%7B%2C%7D00301995...%260%7B%2C%7D00301995...%0A%5Cend%7Barray%7D" alt="\begin{array}{l|l} &HA\left(aq\right)&H_2O\left(l\right)&A^-\left(aq\right)&H_3O^+\left(aq\right)\\ \hline c_{alku}&0{,}11295&-&0&0\\ muutos&-0{,}00301995...&-&+0{,}00301995...&+0{,}00301995...\\ c_{tasap}&0{,}10993&-&0{,}00301995...&0{,}00301995... \end{array}"/><br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=pH%3D2%7B%2C%7D52" alt="pH=2{,}52"/><br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=10%5E%7B-2%7B%2C%7D52%7D%3D0%7B%2C%7D00301995...%3D%5Cleft%5BH_3O%5E%2B%5Cright%5D" alt="10^{-2{,}52}=0{,}00301995...=\left[H_3O^+\right]"/></div>
<div>4.<br/>
<div>yksikkötarkastelu</div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cfrac%7B%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%5Ccdot%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%7B%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%3D%5Cfrac%7Bmol%7D%7Bdm%5E3%7D" alt="\frac{\frac{mol}{dm^3}\cdot\frac{mol}{dm^3}}{\frac{mol}{dm^3}}=\frac{mol}{dm^3}"/></div>
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<div><img src="https://math-demo.abitti.fi/math.svg?latex=K_a%3D%5Cfrac%7B%5Cleft%5BA%5E-%5Cright%5D%5Cleft%5BH_3O%5E%2B%5Cright%5D%7D%7B%5Cleft%5BHA%5Cright%5D%7D%5CRightarrow%5C%20%5Cfrac%7B0%7B%2C%7D11295%5E2%7D%7B0%7B%2C%7D11295%7D%3D0%7B%2C%7D11295" alt="K_a=\frac{\left[A^-\right]\left[H_3O^+\right]}{\left[HA\right]}\Rightarrow\ \frac{0{,}11295^2}{0{,}11295}=0{,}11295"/><br/>
<div>jodihappo, jonka happovakio on 0,17mol/dm^3</div>
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<div> </div>
<div> <br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=K_a%3D%5Cfrac%7B%5Cleft%5BA%5E-%5Cright%5D%5Cleft%5BH_3O%5E%2B%5Cright%5D%7D%7B%5Cleft%5BHA%5Cright%5D%7D%5CRightarrow%5C%20%5Cfrac%7B0%7B%2C%7D0301995...%5E2%7D%7B0%7B%2C%7D10993%7D%3D8%7B%2C%7D296...%5Ccdot10%5E%7B-5%7D" alt="K_a=\frac{\left[A^-\right]\left[H_3O^+\right]}{\left[HA\right]}\Rightarrow\ \frac{0{,}0301995...^2}{0{,}10993}=8{,}296...\cdot10^{-5}"/><br/>
benzoehappo, jonka happovakio on 6,5*10^-5</div>
</div>
5. ero lasketun arvon ja taulukkokirjan arvon välillä johtuu mittauksen lievästä epätarkkuudesta ja laskujen täydellisestä paikkaansapitämättömyydestä<br/>
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6. Muodostunut suola on emäksinen, sillä ekvivalenttipisteessä pH on yli 7</div>
<div>7.<br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=IO_3%5E-%5Cleft(aq%5Cright)%2BH_3O%5E%2B%5Cleft(aq%5Cright)%5Cxrightleftharpoons%5B%5D%7B%7DHIO_3%5Cleft(aq%5Cright)%2BH_2O%5Cleft(l%5Cright)" alt="IO_3^-\left(aq\right)+H_3O^+\left(aq\right)\xrightleftharpoons[]{}HIO_3\left(aq\right)+H_2O\left(l\right)"/><br/>
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<img src="https://math-demo.abitti.fi/math.svg?latex=C_6H_5COO%5E-%5Cleft(aq%5Cright)%2BH_3O%5E%2B%5Cleft(aq%5Cright)%5Cxrightleftharpoons%5B%5D%7B%7DC_6H_5COOH%5Cleft(aq%5Cright)%2BH_2O%5Cleft(l%5Cright)" alt="C_6H_5COO^-\left(aq\right)+H_3O^+\left(aq\right)\xrightleftharpoons[]{}C_6H_5COOH\left(aq\right)+H_2O\left(l\right)"/></div>
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8. Sopiva indikaattori voisi olla kresolipunainen, ekvivalenttipisteessä pH on 7,82 ja kresolipunaisen värinmuutosalue on 7,3-8,8
2020-11-02T15:48:17+02:00