https://peda.net/id/e50f35081db 2020-11-03T11:49:41+02:00 https://peda.net/:static/535/peda.net.logo.bg.svg <div class="license">Tämän sivun lisenssi <a rel="license" href="https://peda.net/info">Peda.net-yleislisenssi</a></div> https://peda.net/id/0887fb361dc 2020-11-03T13:09:25+02:00 a)<br/> <div><img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(HI%5Cright)%3D%5Cfrac%7B1%7B%2C%7D00mol%7D%7B5%7B%2C%7D00l%7D%3D0%7B%2C%7D20%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D" alt="c\left(HI\right)=\frac{1{,}00mol}{5{,}00l}=0{,}20\ \frac{mol}{dm^3}"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cbegin%7Barray%7D%7Bl%7Cl%7D%0A%26HI%26H_2%26I_2%5C%5C%0A%5Chline%0Ac_%7Balku%7D%260%7B%2C%7D20%26%26%5C%5C%0Amuutos%26-2x%26%2Bx%26%2Bx%5C%5C%0Ac_%7Btasap%7D%26%26%26%0A%5Cend%7Barray%7D" alt="\begin{array}{l|l}&#10;&amp;HI&amp;H_2&amp;I_2\\&#10;\hline&#10;c_{alku}&amp;0{,}20&amp;&amp;\\&#10;muutos&amp;-2x&amp;+x&amp;+x\\&#10;c_{tasap}&amp;&amp;&amp;&#10;\end{array}"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D0%7B%2C%7D015%3D%5Cfrac%7B%5Cleft%5BH_2%5Cright%5D%5Cleft%5BI_2%5Cright%5D%7D%7B%5Cleft%5BHI%5Cright%5D%5E2%7D%3D%5Cfrac%7Bx%5E2%7D%7B%5Cleft(0%7B%2C%7D20-2x%5Cright)%5E2%7D" alt="K_c=0{,}015=\frac{\left[H_2\right]\left[I_2\right]}{\left[HI\right]^2}=\frac{x^2}{\left(0{,}20-2x\right)^2}"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=x%3D0%7B%2C%7D019675" alt="x=0{,}019675"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BHI%5Cright%5D%3D0%7B%2C%7D20%5C%20%5Cfrac%7Bmol%7D%7Bl%7D-2%5Ccdot0%7B%2C%7D019675%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%3D0%7B%2C%7D16065%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="\left[HI\right]=0{,}20\ \frac{mol}{l}-2\cdot0{,}019675\ \frac{mol}{l}=0{,}16065\ \frac{mol}{l}"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(HI%5Cright)%3D5l%5Ccdot0%7B%2C%7D16065%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%3D0%7B%2C%7D80%5C%20mol" alt="n\left(HI\right)=5l\cdot0{,}16065\ \frac{mol}{l}=0{,}80\ mol"/></div> 2020-11-03T13:09:25+02:00 https://peda.net/id/dfccee8c1dc 2020-11-03T13:01:07+02:00 <img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(CO_2%5Cright)%3Dc%5Cleft(H_2%5Cright)%3D%5Cfrac%7B2%7B%2C%7D00%5C%20mol%7D%7B3%7B%2C%7D00l%7D%3D0%7B%2C%7D666....%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="c\left(CO_2\right)=c\left(H_2\right)=\frac{2{,}00\ mol}{3{,}00l}=0{,}666....\ \frac{mol}{l}"/> <br/> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cbegin%7Barray%7D%7Bl%7Cl%7D%0A%26CO_2%26H_2%26CO%26H_2O%5C%5C%0A%5Chline%0Ac_%7Balku%7D%260%7B%2C%7D6666...%260%7B%2C%7D6666...%260%260%5C%5C%0Amuutos%26-x%26-x%26%2Bx%26%2Bx%5C%5C%0Ac_%7Btasap%7D%260%7B%2C%7D6666...-x%260%7B%2C%7D6666...-x%26x%26x%0A%5Cend%7Barray%7D" alt="\begin{array}{l|l}&#10;&amp;CO_2&amp;H_2&amp;CO&amp;H_2O\\&#10;\hline&#10;c_{alku}&amp;0{,}6666...&amp;0{,}6666...&amp;0&amp;0\\&#10;muutos&amp;-x&amp;-x&amp;+x&amp;+x\\&#10;c_{tasap}&amp;0{,}6666...-x&amp;0{,}6666...-x&amp;x&amp;x&#10;\end{array}"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D4%7B%2C%7D39%3D%5Cfrac%7B%5Cleft%5BCO%5Cright%5D%5Cleft%5BH_2O%5Cright%5D%7D%7B%5Cleft%5BCO_2%5Cright%5D%5Cleft%5BH_2%5Cright%5D%7D%3D%5Cfrac%7Bx%5E2%7D%7B%5Cleft(0%7B%2C%7D6666...-x%5Cright)%5E2%7D" alt="K_c=4{,}39=\frac{\left[CO\right]\left[H_2O\right]}{\left[CO_2\right]\left[H_2\right]}=\frac{x^2}{\left(0{,}6666...-x\right)^2}"/></div> <div> </div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=x%3D0%7B%2C%7D45128...%5C%20%5Cleft(tai%5C%20x%3D1%7B%2C%7D27537%5Cright)" alt="x=0{,}45128...\ \left(tai\ x=1{,}27537\right)"/></div> <div>sivuutetaan toinen vaihtoehto, alkukonsentraatio ei voi mennä negatiiviseksi</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BCO_2%5Cright%5D%3D%5Cleft%5BH_2%5Cright%5D%3D0%7B%2C%7D21538...%5Capprox0%7B%2C%7D22%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="\left[CO_2\right]=\left[H_2\right]=0{,}21538...\approx0{,}22\ \frac{mol}{l}"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BCO%5Cright%5D%3D%5Cleft%5BH_2O%5Cright%5D%3D0%7B%2C%7D45128...%5Capprox0%7B%2C%7D45%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="\left[CO\right]=\left[H_2O\right]=0{,}45128...\approx0{,}45\ \frac{mol}{l}"/></div> <div> </div> 2020-11-03T13:01:07+02:00 https://peda.net/id/c6300ed41dc 2020-11-03T12:46:05+02:00 <div>a)<br/> <div>alussa </div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(HCl%5Cright)%3D0%7B%2C%7D20%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="c\left(HCl\right)=0{,}20\ \frac{mol}{l}"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BH_3O%5E%2B%5Cright%5D%3D0%7B%2C%7D20%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="\left[H_3O^+\right]=0{,}20\ \frac{mol}{l}"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(HCl%5Cright)%3DcV%3D0%7B%2C%7D20%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%5Ccdot0%7B%2C%7D00025l%3D0%7B%2C%7D00005mol" alt="n\left(HCl\right)=cV=0{,}20\ \frac{mol}{l}\cdot0{,}00025l=0{,}00005mol"/></div> <div>alussa pH</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=-%5Clg%5Cleft(0%7B%2C%7D20%5Cright)%3D0%7B%2C%7D6989" alt="-\lg\left(0{,}20\right)=0{,}6989"/></div> <div>lopussa </div> <div>kun 250ml pullo täytetään vedellä, tilavuus kasvaa 25ml -&gt; 250ml</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(HCl%5Cright)%3D%5Cfrac%7Bn%7D%7BV%7D%3D%5Cfrac%7B0%7B%2C%7D00005mol%7D%7B0%7B%2C%7D0025l%7D%3D0%7B%2C%7D02%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="c\left(HCl\right)=\frac{n}{V}=\frac{0{,}00005mol}{0{,}0025l}=0{,}02\ \frac{mol}{l}"/></div> <div>lopussa pH</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=-%5Clg%5Cleft(0%7B%2C%7D020%5Cright)%3D1%7B%2C%7D6989" alt="-\lg\left(0{,}020\right)=1{,}6989"/></div> <div> </div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5CDelta%20pH%3D1" alt="\Delta pH=1"/></div> <br/> <br/> b)<br/> <img src="https://math-demo.abitti.fi/math.svg?latex=NH_3%5Cleft(aq%5Cright)%2BH_2O%5Cleft(l%5Cright)%5Cxrightleftharpoons%5B%5D%7B%7DNH_4%5E%2B%5Cleft(aq%5Cright)%2BOH%5E-%5Cleft(aq%5Cright)" alt="NH_3\left(aq\right)+H_2O\left(l\right)\xrightleftharpoons[]{}NH_4^+\left(aq\right)+OH^-\left(aq\right)"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BNH_3%5Cright%5D%3D0%7B%2C%7D50%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="\left[NH_3\right]=0{,}50\ \frac{mol}{l}"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=K_b%3D%5Cfrac%7B%5Cleft%5BNH_4%5E%2B%5Cright%5D%5Cleft%5BOH%5E-%5Cright%5D%7D%7B%5Cleft%5BNH_3%5Cright%5D%7D%3D1%7B%2C%7D8%5Ccdot10%5E%7B-5%7D%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D" alt="K_b=\frac{\left[NH_4^+\right]\left[OH^-\right]}{\left[NH_3\right]}=1{,}8\cdot10^{-5}\ \frac{mol}{dm^3}"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5CRightarrow1%7B%2C%7D8%5Ccdot10%5E%7B-5%7D%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%3D%5Cfrac%7Bx%5E2%7D%7B0%7B%2C%7D5-x%7D" alt="\Rightarrow1{,}8\cdot10^{-5}\frac{mol}{dm^3}=\frac{x^2}{0{,}5-x}"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=x%3D0%7B%2C%7D002991" alt="x=0{,}002991"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=%5Cleft%5BOH%5E-%5Cright%5D%3D0%7B%2C%7D002991%5C%20%5Cfrac%7Bmol%7D%7Bl%7D" alt="\left[OH^-\right]=0{,}002991\ \frac{mol}{l}"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=pOH%3D2%7B%2C%7D5241" alt="pOH=2{,}5241"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=pH%3D14-pOH%3D11%7B%2C%7D475" alt="pH=14-pOH=11{,}475"/> </div> 2020-11-03T12:46:05+02:00 https://peda.net/id/386c3f6c1db 2020-11-03T12:20:39+02:00 <div><img src="https://math-demo.abitti.fi/math.svg?latex=H_2CO_3%2BH_2O%5Cxrightleftharpoons%5B%5D%7B%7DHCO_3%5E-%2BH_3O%5E%2B" alt="H_2CO_3+H_2O\xrightleftharpoons[]{}HCO_3^-+H_3O^+"/></div> <div>jos liuokseen lisätään happoa, oksoniumionikonsentraatio kasvaa ja emäksenä toimiva vetykarbonaatti neutraloi lisätyn hapon</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=HCO_3%5E-%5Cleft(aq%5Cright)%2BH_3O%5E%2B%5Cleft(aq%5Cright)%5CRightarrow%20H_2CO_3%5Cleft(aq%5Cright)%2BH_2O" alt="HCO_3^-\left(aq\right)+H_3O^+\left(aq\right)\Rightarrow H_2CO_3\left(aq\right)+H_2O"/></div> <div>jos liuokseen lisätään emästä eli hydroksidi-ionikonsentraatio kasvaa, oksoniumionit neutraloivat emäksen</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=H_3O%5E%2B%5Cleft(aq%5Cright)%2BOH%5E-%5Cleft(aq%5Cright)%5CRightarrow2%5C%20H_2O%5Cleft(l%5Cright)" alt="H_3O^+\left(aq\right)+OH^-\left(aq\right)\Rightarrow2\ H_2O\left(l\right)"/></div> 2020-11-03T12:20:39+02:00 https://peda.net/id/1d9cbee21db 2020-11-03T12:12:44+02:00 a)<br/> <img src="https://math-demo.abitti.fi/math.svg?latex=CaCO_3%2B2%5C%20HCl%5CRightarrow%20CaCl_2%2BCO_2%2BH_2O" alt="CaCO_3+2\ HCl\Rightarrow CaCl_2+CO_2+H_2O"/><br/> b) c)<br/> <img src="https://i.imgur.com/xE673PU.png"/><br/> reaktion nopeus hetkellä t=100s on 0,00624 g/s<br/> d)<br/> <div>25 sekunnissa reaktioseoksen massa pienenee</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=1%7B%2C%7D20398g-1%7B%2C%7D01g%3D0%7B%2C%7D19398g" alt="1{,}20398g-1{,}01g=0{,}19398g"/></div> <div>sekunnissa massa pienenee</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cfrac%7B0%7B%2C%7D19398%7D%7B25s%7D%3D0%7B%2C%7D0077592g" alt="\frac{0{,}19398}{25s}=0{,}0077592g"/></div> <div>hiilidioksidia muodostuu 0,0078g/s aikavälillä 75-100s</div> <div> </div> 2020-11-03T12:12:44+02:00