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<id>https://peda.net/id/cd3f587e133</id>
<updated>2020-10-21T03:38:56+03:00</updated>
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<title>asdf</title>
<id>https://peda.net/id/3fa7f0fe133</id>
<updated>2020-10-21T04:32:14+03:00</updated>
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<content type="html">1&amp;amp;2&lt;br/&gt;&#10;&lt;img src=&quot;https://i.imgur.com/OhOGPbY.png&quot;/&gt;&lt;br/&gt;&#10;titrausliuosta tarvittiin 9,87ml täydelliseen neutraloitumiseen&lt;br/&gt;&#10;3&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=CH_3COOH%5Cleft(aq%5Cright)%2BNaOH%5Cleft(aq%5Cright)%3DCH_3COONa%5Cleft(aq%5Cright)%2BH_2O%5Cleft(l%5Cright)&quot; alt=&quot;CH_3COOH\left(aq\right)+NaOH\left(aq\right)=CH_3COONa\left(aq\right)+H_2O\left(l\right)&quot;/&gt;&lt;br/&gt;&#10;&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(NaOH%5Cright)%3D0%7B%2C%7D10%5Cfrac%7Bmol%7D%7Bdm%5E3%7D&quot; alt=&quot;c\left(NaOH\right)=0{,}10\frac{mol}{dm^3}&quot;/&gt;&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=V%5Cleft(NaOH%5Cright)%3D9%7B%2C%7D87ml&quot; alt=&quot;V\left(NaOH\right)=9{,}87ml&quot;/&gt;&lt;br/&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(NaOH%5Cright)%3DcV%3D0%7B%2C%7D10%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%5Ccdot0%7B%2C%7D00987l%3D0%7B%2C%7D000987mol&quot; alt=&quot;n\left(NaOH\right)=cV=0{,}10\ \frac{mol}{dm^3}\cdot0{,}00987l=0{,}000987mol&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(CH_3COOH%5Cright)%3Dn%5Cleft(NaOH%5Cright)%3D0%7B%2C%7D000987mol&quot; alt=&quot;n\left(CH_3COOH\right)=n\left(NaOH\right)=0{,}000987mol&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=V%5Cleft(CH_3COOH%5Cright)%3D10ml%3D0%7B%2C%7D01l&quot; alt=&quot;V\left(CH_3COOH\right)=10ml=0{,}01l&quot;/&gt;&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=c%3D%5Cfrac%7Bn%7D%7BV%7D%3D%5Cfrac%7B0%7B%2C%7D000987mol%7D%7B0%7B%2C%7D01l%7D%3D0%7B%2C%7D0987%5Cfrac%7Bmol%7D%7Bdm%5E3%7D&quot; alt=&quot;c=\frac{n}{V}=\frac{0{,}000987mol}{0{,}01l}=0{,}0987\frac{mol}{dm^3}&quot;/&gt;&lt;br/&gt;&#10;&lt;br/&gt;&#10;4&lt;br/&gt;&#10;ekvivalenttipisteen pH-arvo on 8,35&lt;br/&gt;&#10;sopiva indikaattori voisi olla fenoliftaleiini, jonka värinmuutosalue on 8,3-10,0&lt;br/&gt;&#10;5&lt;br/&gt;&#10;asetaatti-ioni on lievästi emäksinen, siksi pH-arvo ekvivalenttipisteessä on hieman yli 7&lt;/div&gt;&#10;</content>
<published>2020-10-21T04:32:14+03:00</published>
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