3.1 Tasapainovakion ratkaiseminen ja reaktion suunnan ennustaminen
https://peda.net/id/bdefcdaa047
2020-10-02T08:33:03+03:00
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<div class="license">Tämän sivun lisenssi <a rel="license" href="https://peda.net/info">Peda.net-yleislisenssi</a></div>
3.7
https://peda.net/id/fd958a84047
2020-10-02T09:53:34+03:00
<img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(N_2O_4%5Cright)%3D%5Cfrac%7B24%7B%2C%7D4mmol%7D%7B0%7B%2C%7D372l%7D%3D0%7B%2C%7D06559139..." alt="c\left(N_2O_4\right)=\frac{24{,}4mmol}{0{,}372l}=0{,}06559139..."/><br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(NO_2%5Cright)%3D0%7B%2C%7D0016136" alt="c\left(NO_2\right)=0{,}0016136"/><br/>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cbegin%7Barray%7D%7Bl%7Cl%7D%0A%26N_2O_4%262%5C%20NO_2%5C%5C%0A%5Chline%0Ac_%7Balku%7D%260%7B%2C%7D065591%260%5C%5C%0Amuutos%26-%5Cfrac%7B1%7D%7B2%7D%5Ccdot0%7B%2C%7D016136%26%2B0%7B%2C%7D016136%5C%5C%0Ac_%7Btasap%7D%260%7B%2C%7D057523%260%7B%2C%7D16136%0A%5Cend%7Barray%7D" alt="\begin{array}{l|l} &N_2O_4&2\ NO_2\\ \hline c_{alku}&0{,}065591&0\\ muutos&-\frac{1}{2}\cdot0{,}016136&+0{,}016136\\ c_{tasap}&0{,}057523&0{,}16136 \end{array}"/></div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Cleft(NO_2%5Cright)%5E2%7D%7BN_2O_4%7D%3D0%7B%2C%7D04526371...%5Capprox0%7B%2C%7D453%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D" alt="K_c=\frac{\left(NO_2\right)^2}{N_2O_4}=0{,}04526371...\approx0{,}453\ \frac{mol}{dm^3}"/></div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Cleft(%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%5Cright)%5E2%7D%7B%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%7D%3D%5Cfrac%7Bmol%7D%7Bdm%5E3%7D" alt="K_c=\frac{\left(\frac{mol}{dm^3}\right)^2}{\frac{mol}{dm^3}}=\frac{mol}{dm^3}"/></div>
2020-10-02T09:53:34+03:00
3.3
https://peda.net/id/dbe74706047
2020-10-02T09:26:47+03:00
<img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(NO%5Cright)%3D0%7B%2C%7D100mol" alt="n\left(NO\right)=0{,}100mol"/><br/>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(H_2%5Cright)%3D0%7B%2C%7D0500mol" alt="n\left(H_2\right)=0{,}0500mol"/></div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(H_2O%5Cright)%3D0%7B%2C%7D100mol" alt="n\left(H_2O\right)=0{,}100mol"/><br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(NO%5Cright)%3D0%7B%2C%7D062mol%5Ctext%7B%2F%7Dl" alt="c\left(NO\right)=0{,}062mol\text{/}l"/></div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cbegin%7Barray%7D%7Bl%7Cl%7D%0A%26NO%26H_2%26N_2%26H_2O%5C%5C%0A%5Chline%0Ac_%7Balku%7D%260%7B%2C%7D100%260%7B%2C%7D05%260%260%7B%2C%7D1%5C%5C%0Amuutos%26-0%7B%2C%7D038%26-0%7B%2C%7D038%260%7B%2C%7D038%26%2B0%7B%2C%7D038%5C%5C%0Ac_%7Btasap.%7D%260%7B%2C%7D062%260%7B%2C%7D012%260%7B%2C%7D038%260%7B%2C%7D138%0A%5Cend%7Barray%7D" alt="\begin{array}{l|l} &NO&H_2&N_2&H_2O\\ \hline c_{alku}&0{,}100&0{,}05&0&0{,}1\\ muutos&-0{,}038&-0{,}038&0{,}038&+0{,}038\\ c_{tasap.}&0{,}062&0{,}012&0{,}038&0{,}138 \end{array}"/><br/>
typen tasapainokonsentraatio 0,038 mol/l<br/>
vedyn tasapainokonsentraatio 0,012mol/l<br/>
veden tasapainokonsentraatio 0,138mol/l</div>
<div>b)</div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B0%7B%2C%7D038%5Ccdot0%7B%2C%7D138%7D%7B0%7B%2C%7D062%5Ccdot0%7B%2C%7D012%7D%3D7%7B%2C%7D04838...%5Capprox7%7B%2C%7D05" alt="K_c=\frac{0{,}038\cdot0{,}138}{0{,}062\cdot0{,}012}=7{,}04838...\approx7{,}05"/></div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Ctext%7Bmol%2Fdm%7D%5Ccdot%5Ctext%7Bmol%2Fdm%7D%5E3%7D%7B%5Ctext%7Bmol%2Fdm%7D%5E3%5Ccdot%5Ctext%7Bmol%2Fdm%7D%5E3%7D%3D1" alt="K_c=\frac{\text{mol/dm}\cdot\text{mol/dm}^3}{\text{mol/dm}^3\cdot\text{mol/dm}^3}=1"/><br/>
tasapainovakio on 7,05</div>
2020-10-02T09:16:50+03:00
3.2
https://peda.net/id/37eb1bb0047
2020-10-02T09:05:06+03:00
<img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(N_2%5Cright)%3D2%7B%2C%7D80%5Ccdot10%5E%7B-3%7Dmol" alt="n\left(N_2\right)=2{,}80\cdot10^{-3}mol"/><br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(O_2%5Cright)%3D2%7B%2C%7D5%5Ccdot10%5E%7B-5%7Dmol" alt="n\left(O_2\right)=2{,}5\cdot10^{-5}mol"/><br/>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(N_2O%5Cright)%3D2%7B%2C%7D00%5Ccdot10%5E%7B-2%7Dmol" alt="n\left(N_2O\right)=2{,}00\cdot10^{-2}mol"/></div>
<div><img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Cleft(2%7B%2C%7D00%5Ccdot10%5E%7B-2%7D%5Cright)%5E2%7D%7B%5Cleft(2%7B%2C%7D80%5Ccdot10%5E%7B-3%7D%5Cright)%5E2%5Ccdot2%7B%2C%7D5%5Ccdot10%5E%7B-5%7D%7D%3D2%7B%2C%7D04%5Ccdot10%5E6%5C%20dm%5E3%5Ctext%7B%2F%7Dmol" alt="K_c=\frac{\left(2{,}00\cdot10^{-2}\right)^2}{\left(2{,}80\cdot10^{-3}\right)^2\cdot2{,}5\cdot10^{-5}}=2{,}04\cdot10^6\ dm^3\text{/}mol"/></div>
<div> </div>
2020-10-02T09:05:06+03:00
3.1
https://peda.net/id/0cb109a6047
2020-10-02T08:56:44+03:00
a)<br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=2%5C%20HI%5Cleft(g%5Cright)%5Cxrightleftharpoons%5B%5D%7B%7DH_2%5Cleft(g%5Cright)%2BI_2%5Cleft(g%5Cright)" alt="2\ HI\left(g\right)\xrightleftharpoons[]{}H_2\left(g\right)+I_2\left(g\right)"/><br/>
b)<br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Cleft%5BH_2%5Cright%5D%5C%20%5Ccdot%5Cleft%5BI_2%5Cright%5D%7D%7B%5Cleft%5BHI%5Cright%5D%5E2%7D%3D%5Cfrac%7B%5Cleft(4%7B%2C%7D79%5Ccdot10%5E%7B-4%7Dmol%5Cright)%5E2%7D%7B%5Cleft(3%7B%2C%7D53%5Ccdot10%5E%7B-4%7Dmol%5Cright)%5E2%7D%3D1%7B%2C%7D8412875...%5Capprox1%7B%2C%7D84" alt="K_c=\frac{\left[H_2\right]\ \cdot\left[I_2\right]}{\left[HI\right]^2}=\frac{\left(4{,}79\cdot10^{-4}mol\right)^2}{\left(3{,}53\cdot10^{-4}mol\right)^2}=1{,}8412875...\approx1{,}84"/><br/>
<img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Ctext%7Bmol%2Fdm%7D%5Ccdot%5Ctext%7Bmol%2Fdm%7D%5E3%7D%7B%5Cleft(%5Ctext%7Bmol%2Fdm%7D%5E3%5Cright)%5E2%7D%3D1" alt="K_c=\frac{\text{mol/dm}\cdot\text{mol/dm}^3}{\left(\text{mol/dm}^3\right)^2}=1"/>
2020-10-02T08:56:44+03:00