https://peda.net/id/835b4f98b58 2022-04-06T11:49:43+03:00 https://peda.net/:static/535/peda.net.logo.bg.svg <div class="license">Tämän sivun lisenssi <a rel="license" href="https://peda.net/id/FGdQ44">e-Oppi -lisenssi</a></div> https://peda.net/id/835bdf13b58 2017-09-06T11:38:19+03:00 ​<iframe width="560" height="315" src="https://www.youtube.com/embed/sHas-5hmCi4?rel=0&amp;showinfo=0" allowfullscreen="allowfullscreen"></iframe>​ 2022-04-06T11:49:43+03:00 https://peda.net/id/835c550cb58 2019-07-19T13:46:20+03:00 <b>Supistamista</b><br/> <br/> Murtoluku [[$\dfrac{32}{64}$]] <br/> <br/> voidaan varmuudella supistaa luvulla 2, koska osoittaja ja nimittäjä <br/> ovat parillisia.<br/> <br/> [[$\dfrac{32}{64}^{(2}$]] = [[$\dfrac{32 : 2}{64 : 2}$]] = [[$\dfrac{16}{32}$]]<br/> <br/> supistetaan edelleen luvulla 2 <br/> <br/> [[$\dfrac{16}{32}^{(2}$]] = [[$\dfrac{16 : 2}{32 : 2}$]] = [[$\dfrac{8}{16}$]]<br/> <br/> supistetaan edelleen luvulla 2 <br/> <br/> [[$\dfrac{8}{16}^{(2}$]] = [[$\dfrac{8 : 2}{16 : 2}$]] = [[$\dfrac{4}{8}$]]<br/> <br/> supistetaan edelleen luvulla 2 <br/> <br/> [[$\dfrac{4}{8}^{(2}$]] = [[$\dfrac{4 : 2}{8 : 2}$]] = [[$\dfrac{2}{4}$]]<br/> <br/> supistetaan edelleen luvulla 2 <br/> <br/> [[$\dfrac{2}{4}^{(2}$]] = [[$\dfrac{2 : 2}{4 : 2}$]] = [[$\dfrac{1}{2}$]]<br/> <br/> Samaan tulokseen olisi päätynyt, jos olisi keksinyt, että murtoluvun [[$\dfrac{32}{64}$]]<br/> <br/> voi supistaa luvulla 32 <br/> <br/> [[$\dfrac{32}{64}^{(32}$]] = [[$\dfrac{32 : 32}{64 : 32}$]] = [[$\dfrac{1}{2}$]] 2022-04-06T11:49:43+03:00