<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="https://peda.net/:static/535/atom.xsl"?>
<feed xmlns="http://www.w3.org/2005/Atom">
<title>03. Ohmin laki ja resistanssi</title>
<id>https://peda.net/id/7ca9859edf6</id>
<updated>2019-09-30T14:35:27+03:00</updated>
<link href="https://peda.net/id/7ca9859edf6:atom" rel="self" />
<link href="https://peda.net/p/oskari.lahtinen/fy3s-s%C3%A4hk%C3%B6/3oljr#top" rel="alternate" />
<logo>https://peda.net/:static/535/peda.net.logo.bg.svg</logo>
<rights type="html">&lt;div class=&quot;license&quot;&gt;Tämän sivun lisenssi &lt;a rel=&quot;license&quot; href=&quot;https://peda.net/info&quot;&gt;Peda.net-yleislisenssi&lt;/a&gt;&lt;/div&gt;&#10;</rights>

<entry>
<title>oispa ruokaa</title>
<id>https://peda.net/id/d7b23000df6</id>
<updated>2019-09-26T10:16:01+03:00</updated>
<link href="https://peda.net/p/oskari.lahtinen/fy3s-s%C3%A4hk%C3%B6/3oljr/oispa-ruokaa#top" />
<content type="html">3-2&lt;br/&gt;&#10;a) ei, jännitehäviötä ei tiedetä&lt;br/&gt;&#10;b) joo&lt;br/&gt;&#10;c) ei&lt;br/&gt;&#10;d) joo&lt;br/&gt;&#10;&lt;br/&gt;&#10;3-3&lt;br/&gt;&#10;a)&lt;br/&gt;&#10;A 4,5V&lt;br/&gt;&#10;B 3V&lt;br/&gt;&#10;b)&lt;br/&gt;&#10;A 35mA&lt;br/&gt;&#10;B 50mA&lt;br/&gt;&#10;c) &lt;br/&gt;&#10;vastuslangat noudattavat Ohmin lakia, sillä kuvaajat ovat suoria&lt;br/&gt;&#10;&lt;br/&gt;&#10;3-4&lt;br/&gt;&#10;sininen lanka:&lt;br/&gt;&#10;I=10mA &lt;br/&gt;&#10;U=3,5V&lt;br/&gt;&#10;R=U/I&lt;br/&gt;&#10;R=&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=%5Cfrac%7B3%7B%2C%7D5V%7D%7B0%7B%2C%7D010A%7D%3D350%5COmega&quot; alt=&quot;\frac{3{,}5V}{0{,}010A}=350\Omega&quot;/&gt;&lt;br/&gt;&#10;punainen lanka:&lt;br/&gt;&#10;I=20mA&lt;br/&gt;&#10;U=3V&lt;br/&gt;&#10;R=&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=%5Cfrac%7B3%7B%2C%7D0V%7D%7B0%7B%2C%7D020A%7D%3D150%5COmega&quot; alt=&quot;\frac{3{,}0V}{0{,}020A}=150\Omega&quot;/&gt;&lt;br/&gt;&#10;&lt;br/&gt;&#10;&lt;br/&gt;&#10;3-5&lt;br/&gt;&#10;a)&lt;br/&gt;&#10;&lt;a href=&quot;https://peda.net/p/oskari.lahtinen/fy3s-s%C3%A4hk%C3%B6/3oljr/oispa-ruokaa/sieppaa-png#top&quot; title=&quot;Sieppaa.PNG&quot;&gt;&lt;img src=&quot;https://peda.net/p/oskari.lahtinen/fy3s-s%C3%A4hk%C3%B6/3oljr/oispa-ruokaa/sieppaa-png:file/photo/1a79152c88ce7aab7bd3375a2761ac3b9cff7ea6/Sieppaa.PNG&quot; alt=&quot;&quot; title=&quot;Sieppaa.PNG&quot; class=&quot;inline&quot; loading=&quot;lazy&quot;/&gt;&lt;/a&gt;&lt;br/&gt;&#10;b) kulmakertoimesta saadaan resistanssi 0,0218V/mA, eli 21,8 ohmia&lt;br/&gt;&#10;c) &lt;a href=&quot;https://peda.net/p/oskari.lahtinen/fy3s-s%C3%A4hk%C3%B6/3oljr/oispa-ruokaa/sieppaa-png2#top&quot; title=&quot;Sieppaa.PNG&quot;&gt;&lt;img src=&quot;https://peda.net/p/oskari.lahtinen/fy3s-s%C3%A4hk%C3%B6/3oljr/oispa-ruokaa/sieppaa-png2:file/photo/0d79b485a8634f42493b6aa2b289faa6665539d5/Sieppaa.PNG&quot; alt=&quot;&quot; title=&quot;Sieppaa.PNG&quot; class=&quot;inline&quot; loading=&quot;lazy&quot;/&gt;&lt;/a&gt;&lt;br/&gt;&#10;&lt;br/&gt;&#10;&lt;br/&gt;&#10;3-7&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=R%3D%5Cfrac%7BU%7D%7BI%7D%3D%5Cfrac%7B4%7B%2C%7D5V%7D%7B0%7B%2C%7D012A%7D%3D375%5COmega&quot; alt=&quot;R=\frac{U}{I}=\frac{4{,}5V}{0{,}012A}=375\Omega&quot;/&gt;&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=U%3DRI%3D375%5COmega%5Ccdot0%7B%2C%7D066A%3D24%7B%2C%7D75V&quot; alt=&quot;U=RI=375\Omega\cdot0{,}066A=24{,}75V&quot;/&gt;&lt;br/&gt;&#10;3-8&lt;br/&gt;&#10;a)&lt;br/&gt;&#10;&lt;a href=&quot;https://peda.net/p/oskari.lahtinen/fy3s-s%C3%A4hk%C3%B6/3oljr/oispa-ruokaa/sieppaa-png3#top&quot; title=&quot;Sieppaa.PNG&quot;&gt;&lt;img src=&quot;https://peda.net/p/oskari.lahtinen/fy3s-s%C3%A4hk%C3%B6/3oljr/oispa-ruokaa/sieppaa-png3:file/photo/6eb72e13edf8fcdf57d312c3a6ec247a35f28196/Sieppaa.PNG&quot; alt=&quot;&quot; title=&quot;Sieppaa.PNG&quot; class=&quot;inline&quot; loading=&quot;lazy&quot;/&gt;&lt;/a&gt;&lt;br/&gt;&#10;b)&lt;br/&gt;&#10;U=RI&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=U%3D220%5COmega%5Ccdot0%7B%2C%7D02A%3D4%7B%2C%7D4V&quot; alt=&quot;U=220\Omega\cdot0{,}02A=4{,}4V&quot;/&gt;&lt;br/&gt;&#10;3-9&lt;br/&gt;&#10;a)&lt;br/&gt;&#10;R=U/I&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=R%3D%5Cfrac%7B7%7B%2C%7D35V%7D%7B1%7B%2C%7D08A%7D%3D6%7B%2C%7D8055...%5COmega&quot; alt=&quot;R=\frac{7{,}35V}{1{,}08A}=6{,}8055...\Omega&quot;/&gt;&lt;br/&gt;&#10;b)&lt;br/&gt;&#10;I=U/R&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=I%3D%5Cfrac%7B15V%7D%7B6%7B%2C%7D8055...%5COmega%7D%3D2%7B%2C%7D2041...A&quot; alt=&quot;I=\frac{15V}{6{,}8055...\Omega}=2{,}2041...A&quot;/&gt;&lt;br/&gt;&#10;c)&lt;br/&gt;&#10;U=RI&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=U%3D6%7B%2C%7D8055...%5COmega%5Ccdot0%7B%2C%7D200A%3D1%7B%2C%7D361...V&quot; alt=&quot;U=6{,}8055...\Omega\cdot0{,}200A=1{,}361...V&quot;/&gt; &lt;br/&gt;&#10;&lt;br/&gt;&#10;3-10&lt;br/&gt;&#10;a) 1,5V&lt;br/&gt;&#10;b) &lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=R%3D%5Cfrac%7BU%7D%7BI%7D%3D%5Cfrac%7B0%7B%2C%7D5V%7D%7B0%7B%2C%7D02mA%7D%3D25%5COmega&quot; alt=&quot;R=\frac{U}{I}=\frac{0{,}5V}{0{,}02mA}=25\Omega&quot;/&gt;&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=R%3D%5Cfrac%7B2%7B%2C%7D5V%7D%7B0%7B%2C%7D05mA%7D%3D50%5COmega&quot; alt=&quot;R=\frac{2{,}5V}{0{,}05mA}=50\Omega&quot;/&gt;&lt;br/&gt;&#10;c) hehkulangan lämpötila kasvaa, joten resistanssikin kasvaa&lt;br/&gt;&#10;3-11&lt;br/&gt;&#10;a) ei noudata, kuvaaja ei ole suora&lt;br/&gt;&#10;b) &lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=R%3D%5Cfrac%7BU%7D%7BI%7D%3D%5Cfrac%7B3%7B%2C%7D0V%7D%7B0%7B%2C%7D04A%7D%3D0%7B%2C%7D012%5C%20%5COmega&quot; alt=&quot;R=\frac{U}{I}=\frac{3{,}0V}{0{,}04A}=0{,}012\ \Omega&quot;/&gt;&lt;br/&gt;&#10;&lt;br/&gt;&#10;&lt;br/&gt;&#10;3-13 &lt;br/&gt;&#10;5600 ohmia</content>
<published>2019-09-25T10:34:00+03:00</published>
</entry>


</feed>