https://peda.net/id/635b3d163dc 2020-01-23T11:40:27+02:00 https://peda.net/:static/535/peda.net.logo.bg.svg <div class="license">Tämän sivun lisenssi <a rel="license" href="https://peda.net/info">Peda.net-yleislisenssi</a></div> https://peda.net/id/95455eb4437 2020-02-04T00:40:34+02:00 <div>1.</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=V%5Cleft(NaOH%5Cright)%5Capprox8%7B%2C%7D3%5C%20ml%3D8%7B%2C%7D3%5Ccdot10%5E%7B-3%7Dl" alt="V\left(NaOH\right)\approx8{,}3\ ml=8{,}3\cdot10^{-3}l"/></div> <img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(NaOH%5Cright)%3D8%7B%2C%7D3%5Ccdot10%5E%7B-3%7Dl%5Ccdot0%7B%2C%7D10%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%3D8%7B%2C%7D3%5Ccdot10%5E%7B-4%7Dmol" alt="n\left(NaOH\right)=8{,}3\cdot10^{-3}l\cdot0{,}10\ \frac{mol}{l}=8{,}3\cdot10^{-4}mol"/> <div>2. </div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=C_6H_5COOH%5Cleft(s%5Cright)%2BNaOH%5Cleft(aq%5Cright)%5Crightarrow%20C_6H_5COONa%5Cleft(aq%5Cright)%2BH_2O%5Cleft(l%5Cright)" alt="C_6H_5COOH\left(s\right)+NaOH\left(aq\right)\rightarrow C_6H_5COONa\left(aq\right)+H_2O\left(l\right)"/> <div><img src="https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(C_6H_5COOH%5Cright)%3Dn%5Cleft(NaOH%5Cright)%3D0%7B%2C%7D10%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%5Ccdot8%7B%2C%7D3%5Ccdot10%5E%7B-3%7D%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%3D8%7B%2C%7D3%5Ccdot10%5E%7B-4%7Dmol" alt="n\left(C_6H_5COOH\right)=n\left(NaOH\right)=0{,}10\ \frac{mol}{l}\cdot8{,}3\cdot10^{-3}\ \frac{mol}{l}=8{,}3\cdot10^{-4}mol"/></div> <div>3.</div> <div>Punnitti määrä</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=m%5Cleft(C_6H_5COOH%5Cright)%3D100mg%3D0%7B%2C%7D100g" alt="m\left(C_6H_5COOH\right)=100mg=0{,}100g"/></div> <img src="https://math-demo.abitti.fi/math.svg?latex=n%3D%5Cfrac%7Bm%7D%7BM%7D%5C%20%5Cxrightleftharpoons%5B%5D%7B%7D%5C%20M%3D%5Cfrac%7Bm%7D%7Bn%7D%3D%5Cfrac%7B0%7B%2C%7D100g%7D%7B8%7B%2C%7D3%5Ccdot10%5E%7B-4%7Dmol%7D%5Capprox120%7B%2C%7D48%5C%20%5Cfrac%7Bg%7D%7Bmol%7D" alt="n=\frac{m}{M}\ \xrightleftharpoons[]{}\ M=\frac{m}{n}=\frac{0{,}100g}{8{,}3\cdot10^{-4}mol}\approx120{,}48\ \frac{g}{mol}"/></div> <div>4.</div> <div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=M%5Cleft(C_6H_5COOH%5Cright)%3D%5Cleft(7%5Ccdot12%7B%2C%7D01%2B6%5Ccdot1%7B%2C%7D001%2B2%5Ccdot16%7B%2C%7D00%5Cright)%5C%20%5Cfrac%7Bg%7D%7Bmol%7D%3D122%7B%2C%7D118%5C%20%5Cfrac%7Bg%7D%7Bmol%7D" alt="M\left(C_6H_5COOH\right)=\left(7\cdot12{,}01+6\cdot1{,}001+2\cdot16{,}00\right)\ \frac{g}{mol}=122{,}118\ \frac{g}{mol}"/></div> 5.</div> <div><br/> <br/> <div> </div> </div> 2020-01-30T18:00:06+02:00