https://peda.net/id/508c19e014f 2020-10-23T09:38:09+03:00 https://peda.net/:static/537/peda.net.logo.bg.svg <div class="license">Tämän sivun lisenssi <a rel="license" href="https://peda.net/info">Peda.net-yleislisenssi</a></div> https://peda.net/id/9773f98a14f 2020-10-23T09:52:46+03:00 a)<br/> <img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(HCl%5Cright)%3D0%7B%2C%7D20%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%3D%5Cleft%5BH_3O%5E%2B%5Cright%5D" alt="c\left(HCl\right)=0{,}20\ \frac{mol}{dm^3}=\left[H_3O^+\right]"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=pH%3D-%5Clg%5Cleft%5BH_3O%5E%2B%5Cright%5D%3D0%7B%2C%7D698" alt="pH=-\lg\left[H_3O^+\right]=0{,}698"/><br/> b)<br/> <img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(HClO_4%5Cright)%3D5%7B%2C%7D6%5Ccdot10%5E%7B-3%7D%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%3D%5Cleft%5BH_3O%5E%2B%5Cright%5D" alt="c\left(HClO_4\right)=5{,}6\cdot10^{-3}\ \frac{mol}{dm^3}=\left[H_3O^+\right]"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=pH%3D2%7B%2C%7D251" alt="pH=2{,}251"/><br/> c)<br/> <img src="https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(HNO_3%5Cright)%3D0%7B%2C%7D025%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%3D%5Cleft%5BH_3O%5E%2B%5Cright%5D" alt="c\left(HNO_3\right)=0{,}025\ \frac{mol}{dm^3}=\left[H_3O^+\right]"/><br/> <img src="https://math-demo.abitti.fi/math.svg?latex=pH%3D1%7B%2C%7D602" alt="pH=1{,}602"/><br/> 2020-10-23T09:47:17+03:00