https://peda.net/id/26108fee11a 2019-11-28T09:03:15+02:00 https://peda.net/:static/532/peda.net.logo.bg.svg <div class="license">Tämän sivun lisenssi <a rel="license" href="https://peda.net/info">Peda.net-yleislisenssi</a></div> https://peda.net/id/ec78769012a 2019-11-29T15:12:41+02:00 <span>10-11</span> <div>a)<br/> <div><img src="https://math-demo.abitti.fi/math.svg?latex=_%7B27%7D%5E%7B57%7DCo%2B_%7B-1%7D%5E0e%5Crightarrow_%7B26%7D%5E%7B57%7DFe%2Bv" alt="_{27}^{57}Co+_{-1}^0e\rightarrow_{26}^{57}Fe+v"/></div> <div>b)</div> <div>Oletetaan neutriinon massa nollaksi. Massavaje lasketaan vähentämällä kobolttiytimen ja sen sieppaaman elektronin yhteenlasketusta massasta rautaytimen massa.</div> <div>Atomien yhdinten massat lasketaan vähentämällä atomimassoista elektronien massat.</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=Q%3D%5CDelta%20mc%5E2" alt="Q=\Delta mc^2"/></div> <img src="https://math-demo.abitti.fi/math.svg?latex=%5CDelta%20m%3D%5Cleft%5Bm%5Cleft(_%7B27%7D%5E%7B57%7DCo%5Cright)-27m_e%2Bm_e%5Cright%5D-%5Cleft%5Bm%5Cleft(_%7B26%7D%5E%7B57%7DFe%5Cright)-26m_e%5Cright%5D" alt="\Delta m=\left[m\left(_{27}^{57}Co\right)-27m_e+m_e\right]-\left[m\left(_{26}^{57}Fe\right)-26m_e\right]"/></div> <img src="https://math-demo.abitti.fi/math.svg?latex=%3Dm%5Cleft(_%7B27%7D%5E%7B57%7DCo%5Cright)-m%5Cleft(_%7B26%7D%5E%7B57%7DFe%5Cright)" alt="=m\left(_{27}^{57}Co\right)-m\left(_{26}^{57}Fe\right)"/> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%3D56%7B%2C%7D936294u-56%7B%2C%7D935396u%3D0%7B%2C%7D000898u" alt="=56{,}936294u-56{,}935396u=0{,}000898u"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=1u%3D931%7B%2C%7D49432%5C%20%5Cfrac%7BMeV%7D%7Bc%5E2%7D" alt="1u=931{,}49432\ \frac{MeV}{c^2}"/></div> <div>Elektronisieppauksessa vapautuva energia on </div> <img src="https://math-demo.abitti.fi/math.svg?latex=Q%3D%5CDelta%20mc%5E2%3D0%7B%2C%7D000898%5Ccdot931%7B%2C%7D49432%5C%20%5Cfrac%7BMeV%7D%7Bc%5E2%7D%5Ccdot%20c%5E2%5Capprox0%7B%2C%7D836MeV" alt="Q=\Delta mc^2=0{,}000898\cdot931{,}49432\ \frac{MeV}{c^2}\cdot c^2\approx0{,}836MeV"/><br/> <div> </div> 2019-11-29T15:12:41+02:00 https://peda.net/id/33f3b49c11a 2019-11-28T09:03:38+02:00 <span>Esimerkki. Kirjoita seuraavien ytimen hajoamisreaktiot</span> <div>a)<img src="https://math-demo.abitti.fi/math.svg?latex=%5E%7B238%7DU" alt="^{238}U"/></div> <div>Isotoopin<img src="https://math-demo.abitti.fi/math.svg?latex=_%7B92%7D%5E%7B238%7DU" alt="_{92}^{238}U"/>α-hajoamisen reaktioyhtälö on</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=_%7B92%7D%5E%7B238%7DU%5Crightarrow_%7B90%7D%5E%7B234%7DTh%2B_2%5E4He" alt="_{92}^{238}U\rightarrow_{90}^{234}Th+_2^4He"/></div> <div> </div> <div>b)Polonium-205</div> <div>Polonium-205 voi hajota kahdella eri tavalla</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=%5Cbeta%5E%2B" alt="\beta^+"/>hajoamisen reaktioyhtälö</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=_%7B84%7D%5E%7B205%7DPo%5Crightarrow_%7B83%7D%5E%7B205%7DBi%2B_%7B%2B1%7D%5E0e%2B%5Cnu" alt="_{84}^{205}Po\rightarrow_{83}^{205}Bi+_{+1}^0e+\nu"/></div> <div>Elektronisieppauksen reaktioyhtälö on</div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=_%7B84%7D%5E%7B205%7DPo%2B_%7B-1%7D%5E0e%5Crightarrow_%7B83%7D%5E%7B205%7DBi%2B%5Cnu" alt="_{84}^{205}Po+_{-1}^0e\rightarrow_{83}^{205}Bi+\nu"/></div> <br/> <div>c)<img src="https://math-demo.abitti.fi/math.svg?latex=%5E%7B209%7DPb" alt="^{209}Pb"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=_%7B82%7D%5E%7B209%7DPb%5Crightarrow_%7B83%7D%5E%7B209%7DBi%2B_%7B-1%7D%5E0e%2B%5Coverline%7B%5Cnu%7D" alt="_{82}^{209}Pb\rightarrow_{83}^{209}Bi+_{-1}^0e+\overline{\nu}"/></div> <div> </div> <div> </div> <br/> <div> </div> 2019-11-28T09:03:38+02:00