https://peda.net/id/1df5fdf0018 2020-09-28T15:07:01+03:00 https://peda.net/:static/537/peda.net.logo.bg.svg <div class="license">Tämän sivun lisenssi <a rel="license" href="https://peda.net/info">Peda.net-yleislisenssi</a></div> https://peda.net/id/0a40dd60018 2020-09-28T15:49:25+03:00 <img src="https://math-demo.abitti.fi/math.svg?latex=K_p%3D%5Cfrac%7Bp_i%5Cleft(N_2%5Cright)%5Ccdot%20p_i%5Cleft(H_2%5Cright)%5E2%7D%7Bp_i%5Cleft(N_2H_4%5Cright)%7D%3Dbar%5E2" alt="K_p=\frac{p_i\left(N_2\right)\cdot p_i\left(H_2\right)^2}{p_i\left(N_2H_4\right)}=bar^2"/> 2020-09-28T15:49:25+03:00 https://peda.net/id/54d80756018 2020-09-28T15:37:12+03:00 <img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Cleft%5BSO_3%5Cright%5D%5E2%7D%7B%5Cleft%5BSO_2%5Cright%5D%5E2%5Cleft%5BO_2%5Cright%5D%7D%3D%5Cleft(%5Ctext%7Bmol%2Fdm%7D%5E3%5Cright)%5E%7B-1%7D%3Ddm%5E3%5Ctext%7B%2F%7Dmol" alt="K_c=\frac{\left[SO_3\right]^2}{\left[SO_2\right]^2\left[O_2\right]}=\left(\text{mol/dm}^3\right)^{-1}=dm^3\text{/}mol"/><br/> <div><img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Cleft%5BH_2%5Cright%5D%5E3%5Cleft%5BCO%5Cright%5D%7D%7B%5Cleft%5BCH_4%5Cright%5D%5Cleft%5BH_2O%5Cright%5D%7D%3D%5Cleft(mol%2Fdm%5E3%5Cright)%5E2%3Dmol%5E2%2Fdm%5E6" alt="K_c=\frac{\left[H_2\right]^3\left[CO\right]}{\left[CH_4\right]\left[H_2O\right]}=\left(mol/dm^3\right)^2=mol^2/dm^6"/></div> <div> </div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Cleft%5BHCOOCH_3%5Cright%5D%5Cleft%5BH_2O%5Cright%5D%7D%7B%5Cleft%5BHCOOH%5Cright%5D%5Cleft%5BCH_3OH%5Cright%5D%7D%3Dei%5C%20yksikk%C3%B6%C3%A4" alt="K_c=\frac{\left[HCOOCH_3\right]\left[H_2O\right]}{\left[HCOOH\right]\left[CH_3OH\right]}=ei\ yksikköä"/></div> <div><img src="https://math-demo.abitti.fi/math.svg?latex=K_c%3D%5Cfrac%7B%5Cleft%5BH_2O%5Cright%5D%5E2%5Cleft%5BCl_2%5Cright%5D%5E2%7D%7B%5Cleft%5BHCl%5Cright%5D%5E4%5Cleft%5BO_2%5Cright%5D%7D%3D%5Cleft(mol%2Fdm%5E3%5Cright)%5E%7B-1%7D%3Ddm%5E3%2Fmol" alt="K_c=\frac{\left[H_2O\right]^2\left[Cl_2\right]^2}{\left[HCl\right]^4\left[O_2\right]}=\left(mol/dm^3\right)^{-1}=dm^3/mol"/></div> 2020-09-28T15:37:12+03:00 https://peda.net/id/a4fd07ec018 2020-09-28T15:25:07+03:00 A a<br/> B d<br/> C d<br/> D d 2020-09-28T15:25:07+03:00