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<title>4.2 Neutraloitumisreaktiot ja titrauskäyrä</title>
<id>https://peda.net/id/0e97a95209f</id>
<updated>2020-10-09T08:55:38+03:00</updated>
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<rights type="html">&lt;div class=&quot;license&quot;&gt;Tämän sivun lisenssi &lt;a rel=&quot;license&quot; href=&quot;https://peda.net/info&quot;&gt;Peda.net-yleislisenssi&lt;/a&gt;&lt;/div&gt;&#10;</rights>

<entry>
<title>4.23</title>
<id>https://peda.net/id/f0aef30a120</id>
<updated>2020-10-19T15:16:39+03:00</updated>
<link href="https://peda.net/p/oskari.lahtinen/krjt/4njt/4-23#top" />
<content type="html">a)&lt;br/&gt;&#10;&lt;img src=&quot;https://i.imgur.com/HNOeHVC.png&quot;/&gt;&lt;br/&gt;&#10;b) &lt;br/&gt;&#10;ekvivalenttipiste (18,17; 5,02)&lt;br/&gt;&#10;18,17 cm^3 typpihappoa</content>
<published>2020-10-19T15:16:39+03:00</published>
</entry>

<entry>
<title>4.22</title>
<id>https://peda.net/id/d4d328420a0</id>
<updated>2020-10-19T15:06:00+03:00</updated>
<link href="https://peda.net/p/oskari.lahtinen/krjt/4njt/4-22#top" />
<content type="html">a)&lt;br/&gt;&#10;&lt;img src=&quot;https://i.imgur.com/BzrhfIo.png&quot;/&gt;&lt;br/&gt;&#10;b)&lt;br/&gt;&#10;ekvivalenttipiste (42,49; 8,49)&lt;br/&gt;&#10;c)&lt;br/&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=0%7B%2C%7D04249%5C%20dm%5E3%5Ccdot0%7B%2C%7D10%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D%3D0%7B%2C%7D004249mol%3D4%7B%2C%7D249mmol&quot; alt=&quot;0{,}04249\ dm^3\cdot0{,}10\ \frac{mol}{dm^3}=0{,}004249mol=4{,}249mmol&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=%5Cfrac%7B0%7B%2C%7D004249mol%7D%7B0%7B%2C%7D0200dm%5E3%7D%3D0%7B%2C%7D21245%5C%20%5Cfrac%7Bmol%7D%7Bdm%5E3%7D&quot; alt=&quot;\frac{0{,}004249mol}{0{,}0200dm^3}=0{,}21245\ \frac{mol}{dm^3}&quot;/&gt;&lt;br/&gt;&#10;d)&lt;br/&gt;&#10;2-hydroksipropaanihappo&lt;br/&gt;&#10;e)&lt;br/&gt;&#10;maitohappo on heikko happo, sillä se on orgaaninen happo&lt;/div&gt;&#10;f)&lt;br/&gt;&#10;kaliumlaktaatti&lt;br/&gt;&#10;g)&lt;br/&gt;&#10;fenoliftaleiini, sen värimuutosalue on 8,3-10,0 ja ekvivalenttipiste on ~8,49</content>
<published>2020-10-09T10:27:05+03:00</published>
</entry>

<entry>
<title>4.18</title>
<id>https://peda.net/id/8a9685b209f</id>
<updated>2020-10-09T09:49:13+03:00</updated>
<link href="https://peda.net/p/oskari.lahtinen/krjt/4njt/4-18#top" />
<content type="html">a)&lt;br/&gt;&#10;&lt;div&gt;vetykloridin konsentraatio&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=%5Cfrac%7B1%7B%2C%7D65%5C%20g%7D%7B36%7B%2C%7D46%5C%20%5Cfrac%7Bg%7D%7Bmol%7D%7D%3D0%7B%2C%7D045255...%5C%20%5Cfrac%7Bmol%7D%7Bl%7D&quot; alt=&quot;\frac{1{,}65\ g}{36{,}46\ \frac{g}{mol}}=0{,}045255...\ \frac{mol}{l}&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(NaOH%5Cright)%3D0%7B%2C%7D350%5C%20%5Cfrac%7Bmol%7D%7Bl%7D&quot; alt=&quot;c\left(NaOH\right)=0{,}350\ \frac{mol}{l}&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;reaktioyhtälö&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=NaOH%5Cleft(aq%5Cright)%2BHCl%5Cleft(aq%5Cright)%5Crightarrow%20NaCl%5Cleft(aq%5Cright)%2BH_2O%5Cleft(l%5Cright)&quot; alt=&quot;NaOH\left(aq\right)+HCl\left(aq\right)\rightarrow NaCl\left(aq\right)+H_2O\left(l\right)&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;vetykloridin määrä&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=0%7B%2C%7D045255...%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%5Ccdot0%7B%2C%7D004l%3D0%7B%2C%7D0001810...mol&quot; alt=&quot;0{,}045255...\ \frac{mol}{l}\cdot0{,}004l=0{,}0001810...mol&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;natriumhydroksidia tarvitaan saman verran&lt;/div&gt;&#10;&lt;div&gt; &lt;/div&gt;&#10;&lt;div&gt; &lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=V%3D%5Cfrac%7Bn%7D%7Bc%7D%3D%5Cfrac%7B0%7B%2C%7D0001810...mol%7D%7B0%7B%2C%7D350%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%7D%3D0%7B%2C%7D00051720...l%5Capprox5%7B%2C%7D17ml&quot; alt=&quot;V=\frac{n}{c}=\frac{0{,}0001810...mol}{0{,}350\ \frac{mol}{l}}=0{,}00051720...l\approx5{,}17ml&quot;/&gt;&lt;br/&gt;&#10;b)&lt;br/&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=c%5Cleft(H_2SO_4%5Cright)%3D%5Cfrac%7B10ml%5Ccdot1%7B%2C%7D25%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%7D%7B100ml%7D%3D0%7B%2C%7D125%5C%20%5Cfrac%7Bmol%7D%7Bl%7D&quot; alt=&quot;c\left(H_2SO_4\right)=\frac{10ml\cdot1{,}25\ \frac{mol}{l}}{100ml}=0{,}125\ \frac{mol}{l}&quot;/&gt;&lt;br/&gt;&#10;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=n%5Cleft(H_2SO_4%5Cright)%3D0%7B%2C%7D025l%5Ccdot0%7B%2C%7D125%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%3D0%7B%2C%7D003125%5C%20mol&quot; alt=&quot;n\left(H_2SO_4\right)=0{,}025l\cdot0{,}125\ \frac{mol}{l}=0{,}003125\ mol&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt; &lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=H_2SO_4%5Cleft(aq%5Cright)%2B2%5C%20NaOH%5Cleft(aq%5Cright)%5Crightarrow%20Na_2SO_4%5Cleft(aq%5Cright)%2B2%5C%20H_2O%5Cleft(l%5Cright)&quot; alt=&quot;H_2SO_4\left(aq\right)+2\ NaOH\left(aq\right)\rightarrow Na_2SO_4\left(aq\right)+2\ H_2O\left(l\right)&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;NaOH tarvitaan tuplasti&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=2%5Ccdot%20n%5Cleft(H_2SO_4%5Cright)%3D0%7B%2C%7D00625mol&quot; alt=&quot;2\cdot n\left(H_2SO_4\right)=0{,}00625mol&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=V%3D%5Cfrac%7Bn%7D%7Bc%7D%3D%5Cfrac%7B0%7B%2C%7D00625%5C%20mol%7D%7B0%7B%2C%7D350%5C%20%5Cfrac%7Bmol%7D%7Bl%7D%7D%3D0%7B%2C%7D017857...l%5Capprox17%7B%2C%7D86ml&quot; alt=&quot;V=\frac{n}{c}=\frac{0{,}00625\ mol}{0{,}350\ \frac{mol}{l}}=0{,}017857...l\approx17{,}86ml&quot;/&gt;&lt;/div&gt;&#10;&lt;/div&gt;&#10;</content>
<published>2020-10-09T09:49:13+03:00</published>
</entry>

<entry>
<title>4.17</title>
<id>https://peda.net/id/b2d580d209f</id>
<updated>2020-10-09T09:14:33+03:00</updated>
<link href="https://peda.net/p/oskari.lahtinen/krjt/4njt/4-17#top" />
<content type="html">&lt;div&gt;a)&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=NH_3%5Cleft(aq%5Cright)%2BCH_3COOH%5Cleft(aq%5Cright)%5Crightarrow%20CH_3COONH_4%5Cleft(aq%5Cright)%2BH_2O%5Cleft(l%5Cright)&quot; alt=&quot;NH_3\left(aq\right)+CH_3COOH\left(aq\right)\rightarrow CH_3COONH_4\left(aq\right)+H_2O\left(l\right)&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;ammoniumasetaatti&lt;/div&gt;&#10;&lt;div&gt;b)&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=2%5C%20Al%5Cleft(OH%5Cright)_3%5Cleft(aq%5Cright)%2B3%5C%20H_2SO_4%5Cleft(aq%5Cright)%5Crightarrow%20Al_2%5Cleft(SO_4%5Cright)_3%5Cleft(aq%5Cright)%2B6H_2O%5Cleft(l%5Cright)&quot; alt=&quot;2\ Al\left(OH\right)_3\left(aq\right)+3\ H_2SO_4\left(aq\right)\rightarrow Al_2\left(SO_4\right)_3\left(aq\right)+6H_2O\left(l\right)&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;alumiinisulfaatti&lt;/div&gt;&#10;&lt;div&gt;c)&lt;/div&gt;&#10;&lt;div&gt;&lt;img src=&quot;https://math-demo.abitti.fi/math.svg?latex=H_3PO_4%5Cleft(aq%5Cright)%2BCa%5Cleft(OH%5Cright)_2%5Cleft(aq%5Cright)%5Crightarrow%20CaHPO_4%5Cleft(aq%5Cright)%2B2%5C%20H_2O%5Cleft(l%5Cright)&quot; alt=&quot;H_3PO_4\left(aq\right)+Ca\left(OH\right)_2\left(aq\right)\rightarrow CaHPO_4\left(aq\right)+2\ H_2O\left(l\right)&quot;/&gt;&lt;/div&gt;&#10;&lt;div&gt;kalsiumvetyfosfaatti&lt;/div&gt;&#10;</content>
<published>2020-10-09T09:14:33+03:00</published>
</entry>


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